JK Flip Flops

• gaoyue

  30 Jun 04, 21:28

  Dunnoe if this is the right place to asl.. Can someone explain to me about JKFF, but above all, how to convert RS to D, JK to D, JK to T FFs.
  
  I got an exam coming up but my text book is outdated on this part, completely not mentioning how to convert. Don't ask why is this so, or why don't I get a new one, etc. Thanks.
• larrenV2.003

  30 Jun 04, 21:29

  Digital Electronics......learn b4 in ITE but i forget liao....
• DevilAngel77

  30 Jun 04, 23:49

  Sorry.. cant help on this...
• gaoyue

  30 Jun 04, 23:56

  ugh sibei dulan there goes like 5 marks le lor.
• Ole

  1 Jul 04, 00:04

  lol, do a search online, u will find what u need, that what i did.
• gaoyue

  1 Jul 04, 00:13

  Originally posted by Ole:

  lol, do a search online, u will find what u need, that what i did.

  i found nothing, dats y i post here.
• Elephunk

  1 Jul 04, 00:13

  Go get a new Text or read your notes.Im sure there are examples.
  
  It's hard to explain over the forums.
• octega

  1 Jul 04, 13:45

  Originally posted by gaoyue:

  Dunnoe if this is the right place to asl.. Can someone explain to me about JKFF, but above all, how to convert RS to D, JK to D, JK to T FFs.
  
  I got an exam coming up but my text book is outdated on this part, completely not mentioning how to convert. Don't ask why is this so, or why don't I get a new one, etc. Thanks.

  I try to explain one, JK to D Conversion
  
  Step 1
  First plot JK-FF table (this is not truth table)
  Input, J & K
  Present State,Q
  Next State, Q+1
  J K Q Q+1
  0 0 0 0
  0 0 1 1
  0 1 0 0
  0 1 1 0
  1 0 0 1
  1 0 1 1
  1 1 0 1
  1 1 1 0
  
  Step 2
  From there derive the excitation table for JK-FF
  Q -> Q+1 J K
  0 0 0 X
  0 1 1 X
  1 0 X 1
  1 1 X 0
  X-Don't care
  
  Step 3
  Now look at D-FF's Table
  D Q Q+1
  0 0 0
  0 1 0
  1 0 1
  1 1 1
  
  Step 4
  Using the JK-FF Excitation table fill up D-FF's Q to Q+1.
  D Q Q+1 J K
  0 0 0 0 X
  0 1 0 X 1
  1 0 1 1 X
  1 1 1 X 0
  
  Step 5
  Use the K-Map, simplified the 2 sets
  D Q J
  0 0 0
  0 1 X
  1 0 1
  1 1 X
  
  D Q K
  0 0 X
  0 1 1
  1 0 X
  1 1 0
  You will get the JK-FF
  J=D, K=D'
  
  This mean that the input signal of the D-FF, D feeds into 2 input of the JK-FF.
  -D signal into J input of the JK-FF
  -Invert D signal into K input of the JK-FF
  Tada! You got a D-FF using JK-FF
  
  I hope you can get what I mean, qutie hard to explain without diagrams.
  
  Repeat the same concept for all types of FF, be it JK to D or T to RS, this concept applies for all.
• pipi & poot-poot

  1 Jul 04, 13:52

  Originally posted by octega:
  
  
  I try to explain one, JK to D Conversion
  
  [b]Step 1
  First plot JK-FF table (this is not truth table)
  Input, J & K
  Present State,Q
  Next State, Q+1
  J K Q Q+1
  0 0 0 0
  0 0 1 1
  0 1 0 0
  0 1 1 0
  1 0 0 1
  1 0 1 1
  1 1 0 1
  1 1 1 0
  
  Step 2
  From there derive the excitation table for JK-FF
  Q -> Q+1 J K
  0 0 0 X
  0 1 1 X
  1 0 X 1
  1 1 X 0
  X-Don't care
  
  Step 3
  Now look at D-FF's Table
  D Q Q+1
  0 0 0
  0 1 0
  1 0 1
  1 1 1
  
  Step 4
  Using the JK-FF Excitation table fill up D-FF's Q to Q+1.
  D Q Q+1 J K
  0 0 0 0 X
  0 1 0 X 1
  1 0 1 1 X
  1 1 1 X 0
  
  Step 5
  Use the K-Map, simplified the 2 sets
  D Q J
  0 0 0
  0 1 X
  1 0 1
  1 1 X
  
  D Q K
  0 0 X
  0 1 1
  1 0 X
  1 1 0
  You will get the JK-FF
  J=D, K=D'
  
  This mean that the input signal of the D-FF, D feeds into 2 input of the JK-FF.
  -D signal into J input of the JK-FF
  -Invert D signal into K input of the JK-FF
  Tada! You got a D-FF using JK-FF
  
  I hope you can get what I mean, qutie hard to explain without diagrams.
  
  Repeat the same concept for all types of FF, be it JK to D or T to RS, this concept applies for all. [/b]

  
  
  WAH SEH!!! impressive man!
  
  *~Clap~Clap~Clap~*
• chunyong

  1 Jul 04, 13:54

  haha, ask EEE students loh, they will know or those who study Com Engine one. too bad i MPE...